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Proof step 3 from proof abs-nodes-one-abs-node (previous step)

# buf = a.alignedsize + 2 * NODE_HEADER_SIZE, abs-node(buf, a) ⊦ abs-nodes(buf, m, a ', ladr ', false) ↔ ladr = @(m, # buf)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ abs-node(buf, nd) ↔ (∃ buf0, buf1. buf = buf0 + buf1 + validtrailer ∧ is-encoded(nodeheader(node-size-headerless(nd), false), buf0) ∧ is-encoded(nd, subarray(buf1, 0, node-size-headerless(nd))) ∧ # buf1 = nd.alignedsize)
Proof step 5:
# buf = a.alignedsize + 2 * NODE_HEADER_SIZE, ∃ buf0, buf1. buf = buf0 + buf1 + validtrailer ∧ is-encoded(nodeheader(node-size-headerless(a), false), buf0) ∧ is-encoded(a, subarray(buf1, 0, node-size-headerless(a))) ∧ # buf1 = a.alignedsize ⊦ abs-nodes(buf, m, a ', ladr ', false) ↔ ladr = @(m, # buf)

Rule argument

spec: abs-node name: abs-node seq: ⊦ abs-node(buf, nd) ↔ (∃ buf0, buf1. buf = buf0 + buf1 + validtrailer ∧ is-encoded (nodeheader(node-size-headerless(nd), false), buf0) ∧ is-encoded (nd, subarray(buf1, 0, node-size-headerless(nd))) ∧ # buf1 = nd.alignedsize) subst: [nd, buf] → [a, buf] flags: <all paths>

Additional information

Used terms: a, buf