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Proof step 10 from proof abs-nodes-one-h (previous step)

lax = ladr + lax0 ⊦ (∃ buf0, buf1. buf = buf0 + buf1 ∧ ( abs-padding(buf0) ∧ abs-nodes(buf1, m + # buf0, a ', lax, weak) ∨ lax ≠ [] ∧ ladr.off = m ∧ ladr.size = # buf0 ∧ abs-node(buf0, a) ∧ abs-nodes(buf1, ladr.off + # buf0, [], lax0, weak))) ↔ (∃ buf0, buf1. buf = buf0 + buf1 ∧ ( abs-padding(buf0) ∧ abs-nodes(buf1, m + # buf0, a ', lax, weak) ∨ lax = @(m, 2 * NODE_HEADER_SIZE + a.alignedsize) ' ∧ abs-node(buf0, a) ∧ abs-nodes(buf1, m + # buf0, [], [], weak))), lax = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
⊦ (∃ buf0, buf1. buf = buf0 + buf1 ∧ ( abs-padding(buf0) ∧ abs-nodes(buf1, m + # buf0, a ', ladr ' + lax0, weak) ∨ ladr.off = m ∧ ladr.size = # buf0 ∧ abs-node(buf0, a) ∧ abs-nodes(buf1, ladr.off + # buf0, [], lax0, weak))) ↔ (∃ buf0, buf1. buf = buf0 + buf1 ∧ ( abs-padding(buf0) ∧ abs-nodes(buf1, m + # buf0, a ', ladr ' + lax0, weak) ∨ ladr ' + lax0 = @(m, 2 * NODE_HEADER_SIZE + a.alignedsize) ' ∧ abs-node(buf0, a) ∧ abs-nodes(buf1, m + # buf0, [], [], weak)))

Rule argument

Additional information

Used simplifier rules: a: ⊦ (lax + lax0) + lax1 = lax + lax0 + lax1; from specification list[laddress-list]% ⊦ ladr ' + lax ≠ []; (s)% ⊦ ladr + lax = ladr ' + lax; (s)