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Proof step 12 from proof abs-nodes-prefix-elim (previous step)

abs-nodes(buf0 + buf1, 0, x0 + z, lax1, boolvar1), abs-nodes(buf0, 0, x0, lax0, false), ∃ lax2. lax0 + lax2 = lax1 ⊦ ∃ lax. lax1 = lax0 + lax ∧ abs-nodes(buf1, # buf0, z, lax, boolvar1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
abs-nodes(buf0, 0, x0, lax0, false), abs-nodes(buf0 + buf1, 0, x0 + z, lax0 + lax, boolvar1) ⊦ abs-nodes(buf1, # buf0, z, lax, boolvar1)

Rule argument

Additional information

Used simplifier rules: a: ⊦ (lax + lax0) + lax1 = lax + lax0 + lax1; from specification list[laddress-list]% ⊦ lax + lax0 = lax + lax1 ↔ lax0 = lax1; (s)