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Proof step 6 from proof abs-nodes-prefix-elim (previous step)

abs-nodes(buf0 + buf1, 0, x1, lax1, boolvar1), abs-nodes(buf0, 0, x0, lax0, false), abs-nodes(buf0, 0, x0, lax0, false) ∧ abs-nodes(buf0 + buf1, 0, x1, lax1, boolvar1) → x0 ⊑ x1 ∧ lax0 ⊑ lax1 ⊦ ∃ x2, lax2. x1 = x0 + x2 ∧ lax1 = lax0 + lax2 ∧ abs-nodes(buf1, # buf0, x2, lax2, boolvar1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
abs-nodes(buf0, 0, x0, lax0, false), abs-nodes(buf0 + buf1, 0, x1, lax1, boolvar1), x0 ⊑ x1, lax0 ⊑ lax1 ⊦ ∃ x2, lax2. x1 = x0 + x2 ∧ lax1 = lax0 + lax2 ∧ abs-nodes(buf1, # buf0, x2, lax2, boolvar1)

Rule argument

Additional information

Used simplifier rules: abs-nodes-unique-strong-h: ⊦ abs-nodes(buf, m, x0, lax0, false) → (abs-nodes(buf, m, x1, lax1, boolvar1) ↔ x0 = x1 ∧ lax0 = lax1);