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Proof step 16 from proof abs-nodes-prefix-h (previous step)

# buf2 = nd.alignedsize + 2 * NODE_HEADER_SIZE, lax0.head = @(m, # buf2), abs-node(buf2, nd), abs-nodes(buf, m + # buf2, x, lax0.tail, boolvar0), abs-nodes((buf2 + buf) + buf1, m, x1, lax1, boolvar1), ∀ buf3, buf1, m, x1, lax1, boolvar1, x0, lax0, boolvar0. # buf3 < #(buf2 + buf) → abs-nodes(buf3 + buf1, m, x1, lax1, boolvar1) ∧ abs-nodes(buf3, m, x0, lax0, boolvar0) → x0 ⊑ x1 ∧ lax0 ⊑ lax1 ⊦ lax0 = [], nd ' + x ⊑ x1 ∧ lax0 ⊑ lax1

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 17:
# buf2 = nd.alignedsize + 2 * NODE_HEADER_SIZE, ladr = @(m, # buf2), lax0 = ladr + lax2, abs-node(buf2, nd), abs-nodes((buf2 + buf) + buf1, m, x1, lax1, boolvar1), abs-nodes(buf, m + # buf2, x, lax2, boolvar0), ∀ buf3, buf1, m, x1, lax1, boolvar1, x0, lax0, boolvar0. # buf3 < #(buf2 + buf) → abs-nodes(buf3 + buf1, m, x1, lax1, boolvar1) ∧ abs-nodes(buf3, m, x0, lax0, boolvar0) → x0 ⊑ x1 ∧ lax0 ⊑ lax1 ⊦ lax0 = [], nd ' + x ⊑ x1 ∧ lax0 ⊑ lax1

Rule argument

spec: list-data, inst: laddress-list name: elim-list-c seq: lax ≠ [] ⊦ ladr = lax.head ∧ lax0 = lax.tail ↔ lax = ladr + lax0 subst: [lax, ladr, lax0] → [lax0, ladr, lax]

Additional information

Used simplifier rules: lax ≠ [] ⊦ ladr = lax.head ∧ lax0 = lax.tail ↔ lax = ladr + lax0; (elim) Used terms: lax0, ladr, lax