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Proof step 19 from proof abs-nodes-prefix-h (previous step)

# buf2 = nd.alignedsize + 2 * NODE_HEADER_SIZE, x1 = [], abs-node(buf2, nd), abs-nodes((buf2 + buf) + buf1, m, x1, lax1, boolvar1), abs-nodes(buf, m + # buf2, x, lax2, boolvar0), ∀ buf3, buf1, m, x1, lax1, boolvar1, x0, lax0, boolvar0. # buf3 < #(buf2 + buf) → abs-nodes(buf3 + buf1, m, x1, lax1, boolvar1) ∧ abs-nodes(buf3, m, x0, lax0, boolvar0) → x0 ⊑ x1 ∧ lax0 ⊑ lax1 ⊦ nd ' + x ⊑ x1 ∧ @(m, # buf2) ' + lax2 ⊑ lax1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
# buf2 = nd.alignedsize + 2 * NODE_HEADER_SIZE, abs-node(buf2, nd), abs-nodes((buf2 + buf) + buf1, m, [], [], boolvar1), abs-nodes(buf, m + # buf2, x, lax2, boolvar0), ∀ buf3, buf1, m, x1, lax1, boolvar1, x0, lax0, boolvar0. # buf3 < #(buf2 + buf) → abs-nodes(buf3 + buf1, m, x1, lax1, boolvar1) ∧ abs-nodes(buf3, m, x0, lax0, boolvar0) → x0 ⊑ x1 ∧ lax0 ⊑ lax1 ⊦

Rule argument

Additional information

Used simplifier rules: abs-nodes-elems-empty-adr-empty-h: ⊦ abs-nodes(buf, m, [], lax, weak) → lax = [];%a: ⊦ (x + y) + z = x + y + z; from specification list% ⊦ a ' + x ≠ []; (s)% ⊦ x ⊑ [] ↔ x = []; (s)