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Proof step 30 from proof abs-nodes-prefix-h (previous step)

# buf2 = nd.alignedsize + 2 * NODE_HEADER_SIZE, (buf2 + buf) + buf1 = buf3 + buf0, lax1.head = @(m0, m1), abs-node(buf2, nd), abs-nodes(buf, m + # buf2, x, lax2, boolvar0), abs-padding(buf3) ∧ abs-nodes(buf0, m + # buf3, nd0 ' + x2, lax1, boolvar1) ∨ lax1 ≠ [] ∧ m0 = m ∧ m1 = # buf3 ∧ abs-node(buf3, nd0) ∧ abs-nodes(buf0, m0 + # buf3, x2, lax1.tail, boolvar1), ∀ buf3, buf1, m, x1, lax1, boolvar1, x0, lax0, boolvar0. # buf3 < #(buf2 + buf) → abs-nodes(buf3 + buf1, m, x1, lax1, boolvar1) ∧ abs-nodes(buf3, m, x0, lax0, boolvar0) → x0 ⊑ x1 ∧ lax0 ⊑ lax1 ⊦ nd ' + x ⊑ nd0 ' + x2 ∧ @(m, # buf2) ' + lax2 ⊑ lax1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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