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Proof step 33 from proof abs-nodes-prefix-h (previous step)

# buf2 = nd.alignedsize + 2 * NODE_HEADER_SIZE, (buf2 + buf) + buf1 = buf3 + buf0, abs-node(buf2, nd), abs-nodes(buf, m + # buf2, x, lax2, boolvar0), abs-nodes(buf0, m + # buf3, nd0 ' + x2, @(m0, m1) ' + lax, boolvar1), abs-padding(buf3), ∀ buf3, buf1, m, x1, lax1, boolvar1, x0, lax0, boolvar0. # buf3 < #(buf2 + buf) → abs-nodes(buf3 + buf1, m, x1, lax1, boolvar1) ∧ abs-nodes(buf3, m, x0, lax0, boolvar0) → x0 ⊑ x1 ∧ lax0 ⊑ lax1 ⊦ nd ' + x ⊑ nd0 ' + x2 ∧ @(m, # buf2) ' + lax2 ⊑ @(m0, m1) ' + lax

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: abs-node name: abs-node-no-abs-padding seq: ⊦ abs-node(buf0, nd) ∧ buf0 + buf1 = buf + buf2 → ¬ abs-padding(buf) subst: [buf0, nd, buf1, buf2, buf] → [buf2, nd, buf + buf1, buf0, buf3] flags: <all paths>

Additional information

Used simplifier rules: ⊦ abs-node(buf, nd0) → (abs-node(buf, nd1) ↔ nd0 = nd1); (s)%append-a: ⊦ (buf + buf0) + buf1 = buf + buf0 + buf1; from specification array-splice[buffer] Used terms: buf2, nd, buf + buf1, buf0, buf3