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Proof step 2 from proof abs-nodes-prefix (previous step)

abs-nodes(buf0, x0, lax0, boolvar0), abs-nodes(buf0 + buf1, x1, lax1, boolvar1) ⊦ x0 ⊑ x1 ∧ lax0 ⊑ lax1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
abs-nodes(buf0 + buf1, 0, x1, lax1, boolvar1), abs-nodes(buf0, 0, x0, lax0, boolvar0) ⊦ x0 ⊑ x1 ∧ lax0 ⊑ lax1

Rule argument

Additional information

Used simplifier rules: abs-nodes: ⊦ abs-nodes(buf, x, lax, weak) ↔ abs-nodes(buf, 0, x, lax, weak);