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Proof step 10 from proof abs-nodes-split-h (previous step)

∃ buf0, buf1. buf = buf0 + buf1 ∧ ( abs-padding(buf0) ∧ abs-nodes(buf1, m + # buf0, nd ' + x + x1, lax, weak) ∨ lax ≠ [] ∧ lax.head.off = m ∧ lax.head.size = # buf0 ∧ abs-node(buf0, nd) ∧ abs-nodes(buf1, m + # buf0, x + x1, lax.tail, weak)), ∀ buf0, m, x0, x1, lax, weak. # buf0 < # buf → abs-nodes(buf0, m, x0 + x1, lax, weak) → (∃ buf2, buf1, lax0, lax1. lax = lax0 + lax1 ∧ buf0 = buf2 + buf1 ∧ abs-nodes(buf2, m, x0, lax0, false) ∧ abs-nodes(buf1, m + # buf2, x1, lax1, weak)) ⊦ ∃ buf0, buf1, lax0, lax1. lax = lax0 + lax1 ∧ buf = buf0 + buf1 ∧ abs-nodes(buf0, m, nd ' + x, lax0, false) ∧ abs-nodes(buf1, m + # buf0, x1, lax1, weak)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
abs-padding(buf1) ∧ abs-nodes(buf0, m + # buf1, nd ' + x + x1, lax, weak) ∨ lax ≠ [] ∧ lax.head.off = m ∧ lax.head.size = # buf1 ∧ abs-node(buf1, nd) ∧ abs-nodes(buf0, lax.head.off + # buf1, x + x1, lax.tail, weak), ∀ buf2, m, x0, x1, lax, weak. # buf2 < #(buf1 + buf0) → abs-nodes(buf2, m, x0 + x1, lax, weak) → (∃ buf3, buf1, lax0, lax1. lax = lax0 + lax1 ∧ buf2 = buf3 + buf1 ∧ abs-nodes(buf3, m, x0, lax0, false) ∧ abs-nodes(buf1, m + # buf3, x1, lax1, weak)) ⊦ ∃ buf3, buf2, lax0, lax1. lax = lax0 + lax1 ∧ buf1 + buf0 = buf3 + buf2 ∧ abs-nodes(buf3, m, nd ' + x, lax0, false) ∧ abs-nodes(buf2, m + # buf3, x1, lax1, weak)

Proof step 10 from proof abs-nodes-split-h (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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