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Proof step 2 from proof abs-nodes-strong-imp-weak-h (previous step)

abs-nodes(buf, m, x, lax, false) ⊦ abs-nodes(buf, m, x, lax, true)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: abs-nodes-unique-strong-h: ⊦ abs-nodes(buf, m, x0, lax0, false) → (abs-nodes(buf, m, x1, lax1, boolvar1) ↔ x0 = x1 ∧ lax0 = lax1);