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Proof step 29 from proof abs-nodes-subarray-failed (previous step)

# buf1 = nd.alignedsize + 2 * NODE_HEADER_SIZE, # buf0 = x0.flashsize, abs-node(buf1, nd), abs-nodes(buf0, m0 + # buf1, x0, lax0, false), ∀ buf2, x, n, m, lax. # buf2 < #(buf1 + buf0) → # buf2 = x.flashsize ∧ n < x.flashsize ∧ abs-nodes(buf2, m, x, lax, false) ∧ is-aligned(n, NODE_HEADER_SIZE) → n = 0 ∨ x = [] ∨ (∃ n0. n0 < # lax ∧ abs-nodes(subarray(buf2, 0, n), m, prefixn(n0, x), prefixn(n0, lax), true)) ⊦ buf1 + buf0 = mkbuf(0), buf1 = mkbuf(0), x0 = [], ¬ # lax0 < 1 ∧ abs-nodes(buf1, m0, prefixn(1, nd ' + x0), prefixn(1, @(m0, # buf1) ' + lax0), true)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 30:
# buf0 = x0.flashsize, # buf1 = nd.alignedsize + 2 * NODE_HEADER_SIZE, abs-node(buf1, nd), abs-nodes(buf0, m0 + # buf1, x0, lax0, false), ∀ buf2, x, n, m, lax. # buf2 < #(buf1 + buf0) → # buf2 = x.flashsize ∧ n < x.flashsize ∧ abs-nodes(buf2, m, x, lax, false) ∧ is-aligned(n, NODE_HEADER_SIZE) → n = 0 ∨ x = [] ∨ (∃ n0. n0 < # lax ∧ abs-nodes(subarray(buf2, 0, n), m, prefixn(n0, x), prefixn(n0, lax), true)) ⊦ buf1 + buf0 = mkbuf(0), buf1 = mkbuf(0), x0 = [], lax0 ≠ [] ∧ abs-nodes(buf1, m0, nd ', @(m0, # buf1) ', true)

Rule argument

Additional information

Used simplifier rules: a: ⊦ (lax + lax0) + lax1 = lax + lax0 + lax1; from specification list[laddress-list]% ⊦ prefixn(1, ladr ') = ladr '; (s)%n ≤ # lax ⊦ prefixn(n, lax + lax0) = prefixn(n, lax); (s)% ⊦ # ladr ' = 0 +1; (s)%a: ⊦ (x + y) + z = x + y + z; from specification list% ⊦ prefixn(1, a ') = a '; (s)%n ≤ # x ⊦ prefixn(n, x + y) = prefixn(n, x); (s)% ⊦ # a ' = 0 +1; (s)% ⊦ # lax = 0 ↔ lax = []; (s)% ⊦ m < 1 ↔ m = 0; (s)