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Proof step 11 from proof abs-nodes-unique-weak-h (previous step)

buf = buf0 + buf1, abs-nodes(buf, m, x1, lax1, true), abs-nodes(buf1, m + # buf0, [], [], true), abs-padding(buf0), ∀ buf0, m, x0, lax0, x1, lax1. # buf0 < # buf → abs-nodes(buf0, m, x0, lax0, true) ∧ abs-nodes(buf0, m, x1, lax1, true) → x0 = x1 ∧ lax0 = lax1 ⊦ [] = x1 ∧ [] = lax1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
abs-nodes(buf1, m + # buf0, [], [], true), abs-nodes(buf1, m + # buf0, x1, lax1, true), abs-padding(buf0), ∀ buf2, m, x0, lax0, x1, lax1. # buf2 < #(buf0 + buf1) → abs-nodes(buf2, m, x0, lax0, true) ∧ abs-nodes(buf2, m, x1, lax1, true) → x0 = x1 ∧ lax0 = lax1 ⊦ [] = x1 ∧ [] = lax1

Rule argument

Additional information

Used simplifier rules: abs-nodes-padding-prefix: ⊦ abs-padding(buf0) → ( abs-nodes(buf0 + buf1, m, x, lax, weak) ↔ abs-nodes(buf1, m + # buf0, x, lax, weak));%append-a: ⊦ (buf + buf0) + buf1 = buf + buf0 + buf1; from specification array-splice[buffer]