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Proof step 47 from proof abs-nodes-unique-weak-h (previous step)

# buf1 = nd.alignedsize + 2 * NODE_HEADER_SIZE, lax0.head = @(m, # buf1), abs-node(buf1, nd), abs-nodes(buf0, m + # buf1, x, lax0.tail, true), abs-nodes(buf1 + buf0, m, nd0 ' + x2, lax1, true), ∀ buf2, m, x0, lax0, x1, lax1. # buf2 < #(buf1 + buf0) → abs-nodes(buf2, m, x0, lax0, true) ∧ abs-nodes(buf2, m, x1, lax1, true) → x0 = x1 ∧ lax0 = lax1 ⊦ lax0 = [], nd ' + x = nd0 ' + x2 ∧ lax0 = lax1

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 48:
# buf1 = nd.alignedsize + 2 * NODE_HEADER_SIZE, ladr = @(m, # buf1), lax0 = ladr + lax2, abs-node(buf1, nd), abs-nodes(buf1 + buf0, m, nd0 ' + x2, lax1, true), abs-nodes(buf0, m + # buf1, x, lax2, true), ∀ buf2, m, x0, lax0, x1, lax1. # buf2 < #(buf1 + buf0) → abs-nodes(buf2, m, x0, lax0, true) ∧ abs-nodes(buf2, m, x1, lax1, true) → x0 = x1 ∧ lax0 = lax1 ⊦ lax0 = [], nd ' + x = nd0 ' + x2 ∧ lax0 = lax1

Rule argument

spec: list-data, inst: laddress-list name: elim-list-c seq: lax ≠ [] ⊦ ladr = lax.head ∧ lax0 = lax.tail ↔ lax = ladr + lax0 subst: [lax, ladr, lax0] → [lax0, ladr, lax]

Additional information

Used simplifier rules: lax ≠ [] ⊦ ladr = lax.head ∧ lax0 = lax.tail ↔ lax = ladr + lax0; (elim) Used terms: lax0, ladr, lax