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Proof step 19 from proof abs-nodes-valid-node (previous step)

is-encoded(nodeheader(m, boolvar0), subarray(buf, 0, NODE_HEADER_SIZE)), range=(buf, NODE_HEADER_SIZE + align↑(m, 2 * NODE_HEADER_SIZE), validtrailer, 0, NODE_HEADER_SIZE), 2 * NODE_HEADER_SIZE + align↑(m, 2 * NODE_HEADER_SIZE) ≤ # buf ⊦ (∃ buf0, buf1. buf = buf0 + buf1 ∧ ( abs-padding(buf0) ∧ abs-nodes(buf1, n + # buf0, nd ' + x0, lax, weak) ∨ lax ≠ [] ∧ lax.head.off = n ∧ lax.head.size = # buf0 ∧ abs-node(buf0, nd) ∧ abs-nodes(buf1, lax.head.off + # buf0, x0, lax.tail, weak))) ↔ (∃ buf0, buf1. buf = buf0 + buf1 ∧ ( boolvar0 ∧ abs-padding(buf0) ∧ abs-nodes(buf1, n + # buf0, nd ' + x0, lax, weak) ∨ # buf0 = 2 * NODE_HEADER_SIZE + nd.alignedsize ∧ lax ≠ [] ∧ lax.head = @(n, # buf0) ∧ ¬ boolvar0 ∧ abs-node(buf0, nd) ∧ abs-nodes(buf1, n + # buf0, x0, lax.tail, weak)))

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Rule argument

spec: laddress name: elim seq: ⊦ m = ladr.off ∧ m0 = ladr.size ↔ ladr = @(m, m0) subst: [ladr, m, m0] → [lax.head, m0, m1]

Additional information

Used simplifier rules: ⊦ m = ladr.off ∧ m0 = ladr.size ↔ ladr = @(m, m0); (elim) Used terms: lax.head, m0, m1