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Proof step 10 from proof abs-padding-abs-nodes-h (previous step)

# buf1 = NODE_HEADER_SIZE, is-aligned(# buf0, 2 * NODE_HEADER_SIZE), is-encoded(nodeheader(# buf0, true), buf1) ⊦ #(buf1 + buf0 + validtrailer) = 0 ∧ lax = [] ∨ (∃ buf3, buf2. buf1 + buf0 + validtrailer = buf3 + buf2 ∧ abs-padding(buf3) ∧ abs-nodes(buf2, m + # buf3, [], lax, weak)) ∨ weak ∧ abs-failed(buf1 + buf0 + validtrailer) ∧ lax = [] ↔ lax = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
# buf1 = NODE_HEADER_SIZE, is-aligned(# buf0, 2 * NODE_HEADER_SIZE), is-encoded(nodeheader(# buf0, true), buf1) ⊦ (∃ buf3, buf2. buf1 + buf0 + validtrailer = buf3 + buf2 ∧ abs-padding(buf3) ∧ abs-nodes(buf2, m + # buf3, [], lax, weak)) ∨ weak ∧ abs-failed(buf1 + buf0 + validtrailer) ∧ lax = [] ↔ lax = []

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ NODE_HEADER_SIZE + n ≠ 0; (s)%append-a: ⊦ (buf + buf0) + buf1 = buf + buf0 + buf1; from specification array-splice[buffer]% ⊦ # validtrailer = NODE_HEADER_SIZE; (s)% ⊦ #(buf + buf0) = # buf + # buf0; (s)