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Proof step 18 from proof abs-padding-abs-nodes-h (previous step)

# buf1 = NODE_HEADER_SIZE, buf1 + buf0 + validtrailer = buf2 + buf, is-aligned(# buf0, 2 * NODE_HEADER_SIZE), is-encoded(nodeheader(# buf0, true), buf1), abs-padding(buf2) ∧ abs-nodes(buf, m + # buf2, nd ' + x0, lax, weak) ∨ lax ≠ [] ∧ lax.head.off = m ∧ lax.head.size = # buf2 ∧ abs-node(buf2, nd) ∧ abs-nodes(buf, lax.head.off + # buf2, x0, lax.tail, weak) ⊦

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 19:
# buf1 = NODE_HEADER_SIZE, buf1 + buf0 + validtrailer = buf2 + buf, lax.head = @(m0, m1), is-aligned(# buf0, 2 * NODE_HEADER_SIZE), is-encoded(nodeheader(# buf0, true), buf1), abs-padding(buf2) ∧ abs-nodes(buf, m + # buf2, nd ' + x0, lax, weak) ∨ lax ≠ [] ∧ m0 = m ∧ m1 = # buf2 ∧ abs-node(buf2, nd) ∧ abs-nodes(buf, m0 + # buf2, x0, lax.tail, weak) ⊦

Rule argument

spec: laddress name: elim seq: ⊦ m = ladr.off ∧ m0 = ladr.size ↔ ladr = @(m, m0) subst: [ladr, m, m0] → [lax.head, m0, m1]

Additional information

Used simplifier rules: ⊦ m = ladr.off ∧ m0 = ladr.size ↔ ladr = @(m, m0); (elim) Used terms: lax.head, m0, m1