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Proof step 32 from proof abs-padding-abs-nodes-h (previous step)

# buf1 = NODE_HEADER_SIZE, # buf2 = nd.alignedsize + 2 * NODE_HEADER_SIZE, buf1 + buf0 + validtrailer = buf2 + buf, abs-node(buf2, nd), abs-nodes(buf, m + # buf2, x0, lax0, weak), is-aligned(# buf0, 2 * NODE_HEADER_SIZE), is-encoded(nodeheader(# buf0, true), buf1) ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 33:
⊦ abs-node(buf, nd) ↔ (∃ buf0, buf1. buf = buf0 + buf1 + validtrailer ∧ is-encoded(nodeheader(node-size-headerless(nd), false), buf0) ∧ is-encoded(nd, subarray(buf1, 0, node-size-headerless(nd))) ∧ # buf1 = nd.alignedsize)
Proof step 34:
# buf2 = nd.alignedsize + 2 * NODE_HEADER_SIZE, # buf1 = NODE_HEADER_SIZE, buf1 + buf0 + validtrailer = buf2 + buf, abs-nodes(buf, m + # buf2, x0, lax0, weak), is-aligned(# buf0, 2 * NODE_HEADER_SIZE), is-encoded(nodeheader(# buf0, true), buf1), ∃ buf0, buf1. buf2 = buf0 + buf1 + validtrailer ∧ is-encoded(nodeheader(node-size-headerless(nd), false), buf0) ∧ is-encoded(nd, subarray(buf1, 0, node-size-headerless(nd))) ∧ # buf1 = nd.alignedsize ⊦

Rule argument

spec: abs-node name: abs-node seq: ⊦ abs-node(buf, nd) ↔ (∃ buf0, buf1. buf = buf0 + buf1 + validtrailer ∧ is-encoded (nodeheader(node-size-headerless(nd), false), buf0) ∧ is-encoded (nd, subarray(buf1, 0, node-size-headerless(nd))) ∧ # buf1 = nd.alignedsize) subst: [nd, buf] → [nd, buf2] flags: <all paths>

Additional information

Used terms: nd, buf2