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Proof step 29 from proof abs-split-by-address-h (previous step)

m0 = m, m1 = # buf1, abs-node(buf1, nd), abs-nodes(buf0, m + # buf1, x2, lax3, boolvar0), ∀ buf2, m, x, lax0, ladr, lax1, boolvar0. # buf2 < #(buf1 + buf0) → abs-nodes(buf2, m, x, lax0 + ladr ' + lax1, boolvar0) → (∃ buf3, buf1, buf4, x0, a, x1. x = x0 + a ' + x1 ∧ # x0 = # lax0 ∧ buf2 = buf3 + buf1 + buf4 ∧ ladr = @(m + # buf3, 2 * NODE_HEADER_SIZE + a.alignedsize) ∧ # buf1 = 2 * NODE_HEADER_SIZE + a.alignedsize ∧ abs-node(buf1, a)) ⊦ ∃ buf, buf2, buf3, a, x0. nd ' + x2 = a ' + x0 ∧ buf1 + buf0 = buf + buf2 + buf3 ∧ @(m0, m1) = @(m + # buf, 2 * NODE_HEADER_SIZE + a.alignedsize) ∧ # buf2 = 2 * NODE_HEADER_SIZE + a.alignedsize ∧ abs-node(buf2, a)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 30:
# buf1 = nd.alignedsize + 2 * NODE_HEADER_SIZE, abs-node(buf1, nd), abs-nodes(buf0, m + # buf1, x2, lax3, boolvar0), ∀ buf2, m, x, lax0, ladr, lax1, boolvar0. # buf2 < #(buf1 + buf0) → abs-nodes(buf2, m, x, lax0 + ladr ' + lax1, boolvar0) → (∃ buf3, buf1, buf4, x0, a, x1. x = x0 + a ' + x1 ∧ # x0 = # lax0 ∧ buf2 = buf3 + buf1 + buf4 ∧ ladr = @(m + # buf3, 2 * NODE_HEADER_SIZE + a.alignedsize) ∧ # buf1 = 2 * NODE_HEADER_SIZE + a.alignedsize ∧ abs-node(buf1, a)) ⊦ ∃ buf, buf2, buf3, a, x0. nd ' + x2 = a ' + x0 ∧ buf1 + buf0 = buf + buf2 + buf3 ∧ @(m, # buf1) = @(m + # buf, 2 * NODE_HEADER_SIZE + a.alignedsize) ∧ # buf2 = 2 * NODE_HEADER_SIZE + a.alignedsize ∧ abs-node(buf2, a)

Rule argument

Additional information

Used simplifier rules: ls-abs-node-buf-size: ⊦ abs-node(buf, nd) → # buf = nd.alignedsize + 2 * NODE_HEADER_SIZE;