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Proof step 1 from proof inj-adr (conclusion)

⊦ @(m0, m1) = @(m2, m3) ↔ m0 = m2 ∧ m1 = m3

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ @(m, m0) = @(m1, m2) ↔ m = m1 ∧ m0 = m2; (ws)