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Proof step 14 from proof abs-node-abs-node-append-subarray (previous step)

# buf = nd1.alignedsize, # buf2 = nd0.alignedsize, # buf1 = NODE_HEADER_SIZE, # buf3 = NODE_HEADER_SIZE, # buf1 = # buf3, buf1 = buf3, subarray((buf2 + validtrailer) + buf0, 0, NODE_HEADER_SIZE + nd1.alignedsize) = buf + validtrailer, is-encoded(nodeheader(node-size-headerless(nd1), false), buf3), is-encoded(nd1, subarray(buf, 0, node-size-headerless(nd1))), is-encoded(nodeheader(node-size-headerless(nd0), false), buf1), is-encoded(nd0, subarray(buf2, 0, node-size-headerless(nd0))), nd1.alignedsize ≤ nd0.alignedsize + # buf0 ⊦ nd0 = nd1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
# buf3 = NODE_HEADER_SIZE, # buf2 = nd0.alignedsize, # buf = nd1.alignedsize, node-size-headerless(nd1) = node-size-headerless(nd0), subarray((buf2 + validtrailer) + buf0, 0, NODE_HEADER_SIZE + nd1.alignedsize) = buf + validtrailer, is-encoded(nd1, subarray(buf, 0, node-size-headerless(nd0))), is-encoded(nodeheader(node-size-headerless(nd0), false), buf3), is-encoded(nd0, subarray(buf2, 0, node-size-headerless(nd0))), nd1.alignedsize ≤ nd0.alignedsize + # buf0 ⊦ nd0 = nd1

Rule argument

Additional information

Used simplifier rules: ⊦ nodeheader(m, boolvar) = nodeheader(m0, boolvar0) ↔ m = m0 ∧ (boolvar ↔ boolvar0); (ws)% ⊦ is-encoded(ndhd, buf) → (is-encoded(ndhd0, buf) ↔ ndhd = ndhd0); (s)