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Proof step 22 from proof abs-node-abs-node-append-subarray (previous step)

# buf1 = NODE_HEADER_SIZE, # buf2 = nd0.alignedsize, nd0 = nd1, is-encoded(nd0, subarray(buf2, 0, node-size-headerless(nd0))), is-encoded(nodeheader(node-size-headerless(nd0), false), buf1), nd1.alignedsize ≤ nd0.alignedsize + # buf0 ⊦ ∃ buf4, buf3. subarray((buf1 + buf2 + validtrailer) + buf0, 0, 2 * NODE_HEADER_SIZE + nd1.alignedsize) = buf4 + buf3 + validtrailer ∧ is-encoded(nodeheader(node-size-headerless(nd1), false), buf4) ∧ is-encoded(nd1, subarray(buf3, 0, node-size-headerless(nd1))) ∧ # buf3 = nd1.alignedsize

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 23:
# buf2 = nd1.alignedsize, # buf1 = NODE_HEADER_SIZE, is-encoded(nodeheader(node-size-headerless(nd1), false), buf1), is-encoded(nd1, subarray(buf2, 0, node-size-headerless(nd1))) ⊦ ∃ buf4, buf3. subarray((buf1 + buf2 + validtrailer) + buf0, 0, 2 * NODE_HEADER_SIZE + nd1.alignedsize) = buf4 + buf3 + validtrailer ∧ is-encoded(nodeheader(node-size-headerless(nd1), false), buf4) ∧ is-encoded(nd1, subarray(buf3, 0, node-size-headerless(nd1))) ∧ # buf3 = nd1.alignedsize

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m ≤ m + n; (s)