[Imprint][Data Privacy Statement][E-Mail]

View long theorem info. View the proof. Back to main index. View the specification. View theorem base summary, View theorem base listing, the used properties by spec, the dependency list, the symbol table,

Proof step 12 from proof abs-node-abs-node (previous step)

# buf4 = nd1.alignedsize, # buf6 = nd0.alignedsize, # buf = NODE_HEADER_SIZE, (buf6 + validtrailer) + buf2 = buf4 + validtrailer + buf3, node-size-headerless(nd1) = node-size-headerless(nd0), is-encoded(nd0, subarray(buf6, 0, node-size-headerless(nd0))), is-encoded(nodeheader(node-size-headerless(nd0), false), buf), is-encoded(nd1, subarray(buf4, 0, node-size-headerless(nd0))) ⊦ buf6 = buf4 ∧ nd0 = nd1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 13:
⊦ (buf + buf0) + buf1 = buf + buf0 + buf1
Proof step 14:
# buf = NODE_HEADER_SIZE, # buf6 = nd0.alignedsize, # buf4 = nd1.alignedsize, buf6 + validtrailer + buf2 = buf4 + validtrailer + buf3, node-size-headerless(nd1) = node-size-headerless(nd0), is-encoded(nd1, subarray(buf4, 0, node-size-headerless(nd0))), is-encoded(nodeheader(node-size-headerless(nd0), false), buf), is-encoded(nd0, subarray(buf6, 0, node-size-headerless(nd0))) ⊦ buf6 = buf4 ∧ nd0 = nd1

Rule argument

spec: array-splice, inst: buffer name: append-a seq: ⊦ (buf + buf0) + buf1 = buf + buf0 + buf1 subst: [buf1, buf0, buf] → [buf2, validtrailer, buf6] flags: <all paths>

Additional information

Used terms: buf2, validtrailer, buf6