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Proof step 5 from proof abs-node-abs-node (previous step)

# buf4 = nd1.alignedsize, # buf6 = nd0.alignedsize, # buf5 = NODE_HEADER_SIZE, # buf = NODE_HEADER_SIZE, buf5 + (buf6 + validtrailer) + buf2 = (buf + buf4 + validtrailer) + buf3, is-encoded(nodeheader(node-size-headerless(nd1), false), buf), is-encoded(nd1, subarray(buf4, 0, node-size-headerless(nd1))), is-encoded(nodeheader(node-size-headerless(nd0), false), buf5), is-encoded(nd0, subarray(buf6, 0, node-size-headerless(nd0))) ⊦ buf5 + buf6 = buf + buf4 ∧ nd0 = nd1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ (buf + buf0) + buf1 = buf + buf0 + buf1
Proof step 7:
# buf = NODE_HEADER_SIZE, # buf5 = NODE_HEADER_SIZE, # buf6 = nd0.alignedsize, # buf4 = nd1.alignedsize, buf5 + (buf6 + validtrailer) + buf2 = buf + (buf4 + validtrailer) + buf3, is-encoded(nd0, subarray(buf6, 0, node-size-headerless(nd0))), is-encoded(nodeheader(node-size-headerless(nd0), false), buf5), is-encoded(nd1, subarray(buf4, 0, node-size-headerless(nd1))), is-encoded(nodeheader(node-size-headerless(nd1), false), buf) ⊦ buf5 + buf6 = buf + buf4 ∧ nd0 = nd1

Rule argument

spec: array-splice, inst: buffer name: append-a seq: ⊦ (buf + buf0) + buf1 = buf + buf0 + buf1 subst: [buf1, buf0, buf] → [buf3, buf4 + validtrailer, buf] flags: <all paths>

Additional information

Used terms: buf3, buf4 + validtrailer, buf