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Proof step 9 from proof abs-node-abs-node (previous step)

# buf4 = nd1.alignedsize, # buf6 = nd0.alignedsize, # buf5 = NODE_HEADER_SIZE, # buf = NODE_HEADER_SIZE, # buf5 = # buf, (buf6 + validtrailer) + buf2 = (buf4 + validtrailer) + buf3, buf5 = buf, is-encoded(nodeheader(node-size-headerless(nd1), false), buf), is-encoded(nd1, subarray(buf4, 0, node-size-headerless(nd1))), is-encoded(nodeheader(node-size-headerless(nd0), false), buf5), is-encoded(nd0, subarray(buf6, 0, node-size-headerless(nd0))) ⊦ buf5 + buf6 = buf + buf4 ∧ nd0 = nd1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
# buf = NODE_HEADER_SIZE, # buf6 = nd0.alignedsize, # buf4 = nd1.alignedsize, (buf6 + validtrailer) + buf2 = (buf4 + validtrailer) + buf3, node-size-headerless(nd1) = node-size-headerless(nd0), is-encoded(nd1, subarray(buf4, 0, node-size-headerless(nd0))), is-encoded(nodeheader(node-size-headerless(nd0), false), buf), is-encoded(nd0, subarray(buf6, 0, node-size-headerless(nd0))) ⊦ buf6 = buf4 ∧ nd0 = nd1

Rule argument

Additional information

Used simplifier rules: append-a: ⊦ (buf + buf0) + buf1 = buf + buf0 + buf1; from specification array-splice[buffer]% ⊦ buf + buf0 = buf + buf1 ↔ buf0 = buf1; (s)%⊦ nodeheader(m, boolvar) = nodeheader(m0, boolvar0) ↔ m = m0 ∧ (boolvar ↔ boolvar0); (ws)% ⊦ is-encoded(ndhd, buf) → (is-encoded(ndhd0, buf) ↔ ndhd = ndhd0); (s)