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Proof step 22 from proof abs-node-subarray-failed (previous step)

# buf1 = nd.alignedsize, # buf0 = NODE_HEADER_SIZE, is-encoded(nodeheader(node-size-headerless(nd), false), buf0), is-encoded(nd, subarray(buf1, 0, node-size-headerless(nd))) ⊦ buf0 + buf1 = buf0 + buf1 ∧ # buf0 = NODE_HEADER_SIZE ∧ (is-garbage-header(buf0) ∨ (∃ ndhd. is-encoded(ndhd, buf0) ∧ # buf1 ≤ align↑(ndhd.size, 2 * NODE_HEADER_SIZE)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 23:
# buf1 = nd.alignedsize, # buf0 = NODE_HEADER_SIZE, align↑(node-size-headerless(nd), 2 * NODE_HEADER_SIZE) < nd.alignedsize, is-encoded(nodeheader(node-size-headerless(nd), false), buf0), is-encoded(nd, subarray(buf1, 0, node-size-headerless(nd))) ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%lf-01: ⊦ m < n ∧ n = n0 → m < n0; (forward) from specification nat-basic%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ m ≤ n ↔ ¬ n < m; (ss)% ⊦ nodeheader(m, boolvar).size = m; (s)% ⊦ is-encoded(ndhd, buf) → (is-encoded(ndhd0, buf) ↔ ndhd = ndhd0); (s)% ⊦ is-encoded(ndhd, buf) → ¬ is-garbage-header(buf); (s)