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Proof step 5 from proof abs-node-subarray-failed (previous step)

# buf1 = nd.alignedsize, # buf0 = NODE_HEADER_SIZE, n < 2 * NODE_HEADER_SIZE + nd.alignedsize, is-aligned(n, NODE_HEADER_SIZE), is-encoded(nodeheader(node-size-headerless(nd), false), buf0), is-encoded(nd, subarray(buf1, 0, node-size-headerless(nd))) ⊦ n = 0, # subarray(buf0 + buf1 + validtrailer, 0, n) ≥ NODE_HEADER_SIZE ∧ is-aligned(# subarray(buf0 + buf1 + validtrailer, 0, n), NODE_HEADER_SIZE) ∧ (∃ buf2, buf3. subarray(buf0 + buf1 + validtrailer, 0, n) = buf2 + buf3 ∧ # buf2 = NODE_HEADER_SIZE ∧ (is-garbage-header(buf2) ∨ (∃ ndhd. is-encoded(ndhd, buf2) ∧ # buf3 ≤ align↑(ndhd.size, 2 * NODE_HEADER_SIZE))))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
# buf0 = NODE_HEADER_SIZE, # buf1 = nd.alignedsize, n < 2 * NODE_HEADER_SIZE + nd.alignedsize, is-aligned(n, NODE_HEADER_SIZE), is-encoded(nd, subarray(buf1, 0, node-size-headerless(nd))), is-encoded(nodeheader(node-size-headerless(nd), false), buf0) ⊦ n = 0, ∃ buf2, buf3. subarray(buf0 + buf1 + validtrailer, 0, n) = buf2 + buf3 ∧ # buf2 = NODE_HEADER_SIZE ∧ (is-garbage-header(buf2) ∨ (∃ ndhd. is-encoded(ndhd, buf2) ∧ # buf3 ≤ align↑(ndhd.size, 2 * NODE_HEADER_SIZE)))

Rule argument

Additional information

Used simplifier rules: m ≠ 0 ⊦ is-aligned(n, m) → (m ≤ n ↔ n ≠ 0); (s)% ⊦ NODE_HEADER_SIZE ≠ 0; (s)% ⊦ n ≥ m ↔ m ≤ n; (s)% ⊦ # subarray(buf, m, n) = n; (s)