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Proof step 3 from proof abs-padding-eq (previous step)

# buf = NODE_HEADER_SIZE, # buf5 = NODE_HEADER_SIZE, (buf5 + buf6 + validtrailer) + buf1 = (buf + buf4 + validtrailer) + buf3, is-aligned(# buf6, 2 * NODE_HEADER_SIZE), is-aligned(# buf4, 2 * NODE_HEADER_SIZE), is-encoded(nodeheader(# buf6, true), buf5), is-encoded(nodeheader(# buf4, true), buf) ⊦ buf5 + buf6 = buf + buf4

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ (buf + buf0) + buf1 = buf + buf0 + buf1
Proof step 5:
# buf5 = NODE_HEADER_SIZE, # buf = NODE_HEADER_SIZE, buf5 + (buf6 + validtrailer) + buf1 = (buf + buf4 + validtrailer) + buf3, is-aligned(# buf4, 2 * NODE_HEADER_SIZE), is-aligned(# buf6, 2 * NODE_HEADER_SIZE), is-encoded(nodeheader(# buf4, true), buf), is-encoded(nodeheader(# buf6, true), buf5) ⊦ buf5 + buf6 = buf + buf4

Rule argument

spec: array-splice, inst: buffer name: append-a seq: ⊦ (buf + buf0) + buf1 = buf + buf0 + buf1 subst: [buf1, buf0, buf] → [buf1, buf6 + validtrailer, buf5] flags: <all paths>

Additional information

Used terms: buf1, buf6 + validtrailer, buf5