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Proof step 3 from proof abs-padding-full (previous step)

# buf1 = NODE_HEADER_SIZE, is-aligned(# buf0, 2 * NODE_HEADER_SIZE), is-encoded(nodeheader(# buf0, true), buf1) ⊦ ∃ buf, buf2. buf1 + buf0 = buf + buf2 ∧ is-encoded(nodeheader(# buf2, true), buf) ∧ is-aligned(# buf2, 2 * NODE_HEADER_SIZE)

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 1 terms: buf1, buf0

Additional information

Used simplifier rules: ⊦ is-encoded(ndhd, buf) → (is-encoded(ndhd0, buf) ↔ ndhd = ndhd0); (s) Used terms: buf1, buf0