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Proof step 16 from proof abs-padding-subarray-failed (previous step)

# buf0 = NODE_HEADER_SIZE, n0 < NODE_HEADER_SIZE + # buf1, is-aligned(n0, NODE_HEADER_SIZE), is-aligned(# buf1, 2 * NODE_HEADER_SIZE), is-encoded(nodeheader(# buf1, true), buf0), # buf1 ≤ n0 ⊦ ∃ buf2, buf3. buf0 + buf1 + subarray(validtrailer, 0, n0 - # buf1) = buf2 + buf3 ∧ # buf2 = NODE_HEADER_SIZE ∧ (is-garbage-header(buf2) ∨ (∃ ndhd. is-encoded(ndhd, buf2) ∧ # buf3 ≤ align↑(ndhd.size, 2 * NODE_HEADER_SIZE)))

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 17:
# buf0 = NODE_HEADER_SIZE, n0 = n1 + # buf1, n0 < NODE_HEADER_SIZE + # buf1, is-aligned(# buf1, 2 * NODE_HEADER_SIZE), is-aligned(n0, NODE_HEADER_SIZE), is-encoded(nodeheader(# buf1, true), buf0), # buf1 ≤ n0 ⊦ ∃ buf2, buf3. buf0 + buf1 + subarray(validtrailer, 0, n1) = buf2 + buf3 ∧ # buf2 = NODE_HEADER_SIZE ∧ (is-garbage-header(buf2) ∨ (∃ ndhd. is-encoded(ndhd, buf2) ∧ # buf3 ≤ align↑(ndhd.size, 2 * NODE_HEADER_SIZE)))

Rule argument

spec: nat name: elim-sub seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [m, n, n0] → [n0, # buf1, n]

Additional information

Used simplifier rules: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n; (elim) Used terms: n0, # buf1, n