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Proof step 112 from proof decode-node (previous step)

⊦ n + m ≤ # buf → (buf0 = subarray(buf, n, m) ↔ (∃ buf1, buf2. buf = buf1 + buf0 + buf2 ∧ # buf1 = n ∧ # buf0 = m))

A spec-lemma