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Proof step 180 from proof encode-node (previous step)

# buf0 = # buf, # buf = n0 + n + 2 * NODE_HEADER_SIZE + nd.alignedsize, subarray(buf0, 0, n) = subarray(buf, 0, n), subarray(buf0, n + NODE_HEADER_SIZE, # buf - n + NODE_HEADER_SIZE) = subarray(buf, n + NODE_HEADER_SIZE, # buf - n + NODE_HEADER_SIZE), n + NODE_HEADER_SIZE ≤ # buf, n + 2 * NODE_HEADER_SIZE + nd.alignedsize ≤ # buf, ⌊err⌋ ⊦ subarray(buf0, n + 2 * NODE_HEADER_SIZE + nd.alignedsize, n0) = subarray(buf, n + 2 * NODE_HEADER_SIZE + nd.alignedsize, n0)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 181:
# buf = n0 + n + 2 * NODE_HEADER_SIZE + nd.alignedsize, # buf0 = # buf, # buf = n1 + n + NODE_HEADER_SIZE, subarray(buf0, n + NODE_HEADER_SIZE, n1) = subarray(buf, n + NODE_HEADER_SIZE, n1), subarray(buf0, 0, n) = subarray(buf, 0, n), n + 2 * NODE_HEADER_SIZE + nd.alignedsize ≤ # buf, n + NODE_HEADER_SIZE ≤ # buf, ⌊err⌋ ⊦ subarray(buf0, n + 2 * NODE_HEADER_SIZE + nd.alignedsize, n0) = subarray(buf, n + 2 * NODE_HEADER_SIZE + nd.alignedsize, n0)

Rule argument

spec: nat name: elim-sub seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [m, n, n0] → [# buf, n + NODE_HEADER_SIZE, n1]

Additional information

Used simplifier rules: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n; (elim) Used terms: # buf, n + NODE_HEADER_SIZE, n1