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Proof step 8 from proof encode-node (previous step)

# buf = n0 + n + 2 * NODE_HEADER_SIZE + nd.alignedsize, n + 2 * NODE_HEADER_SIZE + nd.alignedsize ≤ # buf ⊦ ⟪let m0 = align↑(node-size-headerless(nd), 2 * NODE_HEADER_SIZE), m = ? in {buf1 := buf; encode_header#(nodeheader(node-size-headerless(nd), false), n; buf; err); m3 := n; if err = ESUCCESS then encode_node_headerless#(nd, m3 + NODE_HEADER_SIZE; buf, m; err); if err = ESUCCESS then {buf := fill(buf, empty, m3 + NODE_HEADER_SIZE + node-size-headerless(nd), m0 - node-size-headerless(nd)); buf := copy(validtrailer, 0, buf, m3 + NODE_HEADER_SIZE + m0, NODE_HEADER_SIZE)}; m2 := 2 * NODE_HEADER_SIZE + m0}⟫ ( (err = ESUCCESS ∨ ⌊err⌋ ) ∧ # buf = # buf1 ∧ subarray(buf, 0, n) = subarray(buf1, 0, n) ∧ subarray(buf, n + 2 * NODE_HEADER_SIZE + nd.alignedsize, n0) = subarray(buf1, n + 2 * NODE_HEADER_SIZE + nd.alignedsize, n0) ∧ ( err = ESUCCESS → (∃ buf0, buf1. subarray(buf, n, 2 * NODE_HEADER_SIZE + nd.alignedsize) = buf0 + buf1 + validtrailer ∧ is-encoded(nodeheader(node-size-headerless(nd), false), buf0) ∧ is-encoded(nd, subarray(buf1, 0, node-size-headerless(nd))) ∧ # buf1 = nd.alignedsize) ∧ m2 = 2 * NODE_HEADER_SIZE + nd.alignedsize))

Heuristic symbolic execution applied rule let right

And obtained the following new goals

Rule argument

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