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Proof step 10 from proof crash-neutral-allocate-ind (previous step)

remove-refsize0(istore0) = istore0, remove-refsize0(gstore1) = gstore1, elems nx ∩ ginval1 = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ ginval1, inv(istore0), inv(istore), inv(gstore1), inv(gstore2 \ ginval1), istore0 ⊑ istore, pstate.index? → pstate.lnum ∈ istore, pstate.journal? → nx ≠ [] ∧ pstate.lnum = nx.last ∧ pstate.lnum ∈ gstore2 ⊦ (⌊EIO⌋ ∨ EIO = ESUCCESS) ∧ ⟨err := EIO; istore1 := remove-refsize0(crash(istore, istore0)); if err = ESUCCESS then choose n with ¬ n ∈ istore in istore[n] := indexblock([], [], 0), pstate := index(n)⟩ (istore1 = remove-refsize0(crash(istore, istore0))), dups(nx)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
remove-refsize0(gstore1) = gstore1, remove-refsize0(istore0) = istore0, elems nx ∩ ginval1 = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ ginval1, inv(gstore2 \ ginval1), inv(gstore1), inv(istore), inv(istore0), istore0 ⊑ istore, ¬ dups(nx), pstate.journal? → nx ≠ [] ∧ pstate.lnum = nx.last ∧ pstate.lnum ∈ gstore2, pstate.index? → pstate.lnum ∈ istore ⊦ ⟨err := EIO; istore1 := remove-refsize0(crash(istore, istore0)); if err = ESUCCESS then choose n with ¬ n ∈ istore in istore[n] := indexblock([], [], 0), pstate := index(n)⟩ (istore1 = remove-refsize0(crash(istore, istore0)))

Rule argument

Additional information

Used simplifier rules: ⊦ ⌊EIO⌋ ; (s)