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Proof step 8 from proof crash-neutral-read-gblock (previous step)

syn ↔ true, adr = adr0, ginval = ginval2, ginval0 = ginval1, gstore = gstore1, gstore0 = gstore2, istore = istore1, istore0 = istore2, maxino = maxino1, maxino0 = maxino2, remove-refsize0(istore1) = istore1, remove-refsize0(gstore1) = gstore1, elems nx ∩ ginval1 = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ ginval1, inv(istore1), inv(istore2), inv(gstore1), inv(gstore2 \ ginval1), maxino2 ∈ gstore2, istore1 ⊑ istore2, pstate.index? → pstate.lnum ∈ istore2, pstate.journal? → nx ≠ [] ∧ pstate.lnum = nx.last ∧ pstate.lnum ∈ gstore2 ⊦ (⌊EIO⌋ ∨ EIO = ESUCCESS) ∧ ⟨err := EIO; if err = ESUCCESS then ax := ax + gstore0[maxino0].ladrlist.to-adr(maxino0), gndx := gndx + gstore0[maxino0].gndlist else ax := ?, gndx := ?⟩ true, dups(nx), maxino2 ∈ ginval1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
remove-refsize0(gstore1) = gstore1, remove-refsize0(istore1) = istore1, elems nx ∩ ginval1 = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ ginval1, inv(gstore2 \ ginval1), inv(gstore1), inv(istore2), inv(istore1), maxino2 ∈ gstore2, istore1 ⊑ istore2, ¬ dups(nx), ¬ maxino2 ∈ ginval1, pstate.journal? → nx ≠ [] ∧ pstate.lnum = nx.last ∧ pstate.lnum ∈ gstore2, pstate.index? → pstate.lnum ∈ istore2 ⊦ ⟨err := EIO; if err = ESUCCESS then ax := ax + gstore2[maxino2].ladrlist.to-adr(maxino2), gndx := gndx + gstore2[maxino2].gndlist else ax := ?, gndx := ?⟩ true

Rule argument

Additional information

Used simplifier rules: ⊦ ⌊EIO⌋ ; (s)