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Proof step 42 from proof inv-add-gnds (previous step)

gstore[nx.last] = groupblock(gndx0, lax0, m), remove-refsize0(istore1) = istore1, remove-refsize0(gstore0) = gstore0, elems nx ∩ ginval2 = ∅, dom gstore0 ∪ elems nx = dom gstore ∪ ginval2, inv(groupblock(gndx0, lax0, m)), inv(istore1), inv(istore2), inv(gstore0), inv(gstore \ ginval2), nx.last ∈ gstore, istore1 ⊑ istore2 ⊦ gndx = [], nx = [], dups(nx), ∃ lax, err. (⌊err⌋ ∨ err = ESUCCESS) ∧ ¬ dups(lax0 + lax) ∧ # lax ≤ # gndx ∧ inv-flashsize(prefixn(# lax, gndx), lax) ∧ (err = ESUCCESS ↔ # lax = # gndx)

User applied rule exists right

And closed the goal!

Rule argument

pos: right 4 terms: [], EIO abort: F discard: T computed: F

Additional information

Used simplifier rules: ⊦ ⌊EIO⌋ ; (s)% ⊦ lax + [] = lax; (s)%a: ⊦ (lax + lax0) + lax1 = lax + lax0 + lax1; from specification list[laddress-list]% ⊦ inv(groupblock(gndx, lax, m0)) → ¬ dups(lax); (s)% ⊦ # [] = 0; (s)% ⊦ 0 ≤ m; (s)% ⊦ prefixn(0, gndx) = []; (s)% ⊦ inv-flashsize([], lax) ↔ lax = []; (s)% ⊦ ESUCCESS ≠ EIO; (s)% ⊦ # gndx = 0 ↔ gndx = []; (s) Used terms: [], EIO