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Proof step 10 from proof inv-allocate-ind (previous step)

err0 = ESUCCESS, remove-refsize0(istore0) = istore0, remove-refsize0(gstore1) = gstore1, elems nx ∩ ginval2 = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ ginval2, inv(istore0), inv(istore), inv(gstore1), inv(gstore2 \ ginval2), istore0 ⊑ istore, pstate.index? → pstate.lnum ∈ istore, pstate.journal? → nx ≠ [] ∧ pstate.lnum = nx.last ∧ pstate.lnum ∈ gstore2, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪choose n with ¬ n ∈ istore in istore[n] := indexblock([], [], 0), pstate := index(n)⟫ ( inv(istore) ∧ istore0 ⊑ istore ∧ (pstate.journal? → nx ≠ [] ∧ pstate.lnum = nx.last ∧ pstate.lnum ∈ gstore2) ∧ (pstate.index? → pstate.lnum ∈ istore)), dups(nx)

Heuristic symbolic execution applied rule choose right

And obtained the following new goals

Rule argument

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