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Proof step 14 from proof inv-allocate-ind (previous step)

remove-refsize0(gstore1) = gstore1, remove-refsize0(istore0) = istore0, elems nx ∩ ginval2 = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ ginval2, inv(gstore2 \ ginval2), inv(gstore1), inv(istore), inv(istore0), (dom istore).max + 1 ∈ istore, istore0 ⊑ istore, pstate.journal? → nx ≠ [] ∧ pstate.lnum = nx.last ∧ pstate.lnum ∈ gstore2, pstate.index? → pstate.lnum ∈ istore ⊦ dups(nx)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: nat-store+set, inst: index-store name: dom-max-in seq: ⊦ istore ≠ ∅ ∧ n > (dom istore).max → (n ∈ istore ↔ false) subst: [istore, n] → [istore, (dom istore).max + 1] flags: <all paths>

Additional information

Used simplifier rules: ⊦ m > n ↔ n < m; (s)% ⊦ m < n + 1 ↔ ¬ n < m; (s)% ⊦ ¬ n < n; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic% ⊦ inv(∅); (s)% ⊦ dom ∅ = ∅; (s)% ⊦ ¬ n ∈ ∅; (s) Used terms: istore, (dom istore).max + 1