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Proof step 14 from proof inv-commit (previous step)

err0 = ESUCCESS, remove-refsize0(istore1) = istore1, remove-refsize0(gstore1) = gstore1, elems nx ∩ ginval4 = ∅, dom remove-refsize0(gstore2) ∩ ginval4 = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ ginval4, inv(istore1), inv(istore2), inv(gstore1), inv(gstore2 \ ginval4), istore1 ⊑ istore2, pstate.index? → pstate.lnum ∈ istore2, pstate.journal? → nx ≠ [] ∧ pstate.lnum = nx.last ∧ pstate.lnum ∈ gstore2, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪ginval4 := ∅; adr := adr0; ginval := ginval1; nx := []; maxino := maxino0; pstate := unbuffered; ginval1 := ?⟫ ( inv(remove-refsize0(gstore2) \ ginval4) ∧ inv(remove-refsize0(gstore2)) ∧ elems nx ∩ ginval4 = ∅ ∧ ¬ dups(nx) ∧ dom remove-refsize0(gstore2) ∪ elems nx = dom remove-refsize0(gstore2) ∪ ginval4 ∧ remove-refsize0(remove-refsize0(gstore2)) = remove-refsize0(gstore2) ∧ inv(remove-refsize0(istore2)) ∧ inv(remove-refsize0(istore2)) ∧ remove-refsize0(istore2) ⊑ remove-refsize0(istore2) ∧ remove-refsize0(remove-refsize0(istore2)) = remove-refsize0(istore2) ∧ (pstate.journal? → nx ≠ [] ∧ pstate.lnum = nx.last ∧ pstate.lnum ∈ remove-refsize0(gstore2)) ∧ (pstate.index? → pstate.lnum ∈ remove-refsize0(istore2))), dups(nx)

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Rule argument

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