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Proof step 8 from proof inv-commit (previous step)

remove-refsize0(istore1) = istore1, remove-refsize0(gstore1) = gstore1, elems nx ∩ ginval4 = ∅, dom remove-refsize0(gstore2) ∩ ginval4 = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ ginval4, inv(istore1), inv(istore2), inv(gstore1), inv(gstore2 \ ginval4), istore1 ⊑ istore2, pstate.index? → pstate.lnum ∈ istore2, pstate.journal? → nx ≠ [] ∧ pstate.lnum = nx.last ∧ pstate.lnum ∈ gstore2, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪err := err0; if err = ESUCCESS then {istore2 := remove-refsize0(istore2); istore1 := istore2; gstore2 := remove-refsize0(gstore2); gstore1 := gstore2; ginval4 := ∅; adr := adr0; ginval := ginval1; nx := []; maxino := maxino0; pstate := unbuffered} else pstate := readonly; ginval1 := ?⟫ ( inv(gstore2 \ ginval4) ∧ inv(gstore1) ∧ elems nx ∩ ginval4 = ∅ ∧ ¬ dups(nx) ∧ dom gstore1 ∪ elems nx = dom gstore2 ∪ ginval4 ∧ remove-refsize0(gstore1) = gstore1 ∧ inv(istore2) ∧ inv(istore1) ∧ istore1 ⊑ istore2 ∧ remove-refsize0(istore1) = istore1 ∧ (pstate.journal? → nx ≠ [] ∧ pstate.lnum = nx.last ∧ pstate.lnum ∈ gstore2) ∧ (pstate.index? → pstate.lnum ∈ istore2)), dups(nx)

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Rule argument

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