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Proof step 6 from proof inv-deallocate-gnd (previous step)

syn ↔ true, istore = istore1, istore0 = istore2, remove-refsize0(istore1) = istore1, remove-refsize0(gstore0) = gstore0, elems nx ∩ ginval = ∅, dom gstore0 ∪ elems nx = dom gstore ∪ ginval, inv(istore1), inv(istore2), inv(gstore0), inv(gstore \ ginval), n ∈ gstore0, n ∈ gstore, istore1 ⊑ istore2, pstate.index? → pstate.lnum ∈ istore2, pstate.journal? → nx ≠ [] ∧ pstate.lnum = nx.last ∧ pstate.lnum ∈ gstore ⊦ ⟪choose err0 with ⌊err0⌋ ∨ err0 = ESUCCESS in err := err0; if err = ESUCCESS then gstore := gstore -- n, ginval := ginval ++ n⟫ ( inv(gstore \ ginval) ∧ elems nx ∩ ginval = ∅ ∧ dom gstore0 ∪ elems nx = dom gstore ∪ ginval ∧ (pstate.journal? → nx ≠ [] ∧ pstate.lnum = nx.last ∧ pstate.lnum ∈ gstore) ∧ (pstate.index? → pstate.lnum ∈ istore2)), dups(nx), n ∈ nx

Heuristic symbolic execution applied rule choose right

And obtained the following new goals

Rule argument

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