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Proof step 10 from proof inv-read-gnd (previous step)

remove-refsize0(istore1) = istore1, remove-refsize0(gstore1) = gstore1, elems nx ∩ ginval2 = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ ginval2, inv(istore1), inv(istore2), inv(gstore1), inv(gstore2 \ ginval2), @(m, m0, m1) ∈ gstore2, istore1 ⊑ istore2, pstate = unbuffered → syn, pstate.index? → pstate.lnum ∈ istore2, pstate.journal? → nx ≠ [] ∧ pstate.lnum = nx.last ∧ pstate.lnum ∈ gstore2, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪err := err0; if err = ESUCCESS then gnd := gstore2[@(m, m0, m1)] else gnd := ?⟫ true, dups(nx), m ∈ ginval2

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Proof step 11:
remove-refsize0(gstore1) = gstore1, remove-refsize0(istore1) = istore1, elems nx ∩ ginval2 = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ ginval2, inv(gstore2 \ ginval2), inv(gstore1), inv(istore2), inv(istore1), @(m, m0, m1) ∈ gstore2, istore1 ⊑ istore2, pstate.journal? → nx ≠ [] ∧ pstate.lnum = nx.last ∧ pstate.lnum ∈ gstore2, pstate.index? → pstate.lnum ∈ istore2, pstate = unbuffered → syn, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪if err0 = ESUCCESS then gnd := gstore2[@(m, m0, m1)] else gnd := ?⟫ true, dups(nx), m ∈ ginval2

Proof step 10 from proof inv-read-gnd (previous step)

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Rule argument

Additional information