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Proof step 10 from proof inv-recovery (previous step)

adr0 = adr1, ginval = ginval4, ginval0 = ginval2, ginval1 = ginval3, gstore = gstore1, gstore0 = gstore3, gstore3 = crash(gstore2, gstore1, ginval4, nx), istore = istore1, istore0 = istore3, istore3 = remove-refsize0(crash(istore2, istore1)), maxino0 = maxino1, nx0 = nx1, remove-refsize0(istore1) = istore1, remove-refsize0(gstore1) = gstore1, elems nx ∩ ginval4 = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ ginval4, inv(istore1), inv(istore2), inv(gstore1), inv(gstore2 \ ginval4), istore1 ⊑ istore2, pstate.index? → pstate.lnum ∈ istore2, pstate.journal? → nx ≠ [] ∧ pstate.lnum = nx.last ∧ pstate.lnum ∈ gstore2 ⊦ dups(nx), ∃ err0. ⌊err0⌋ ∨ err0 = ESUCCESS

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
remove-refsize0(gstore1) = gstore1, remove-refsize0(istore1) = istore1, elems nx ∩ ginval4 = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ ginval4, inv(gstore2 \ ginval4), inv(gstore1), inv(istore2), inv(istore1), istore1 ⊑ istore2, pstate.journal? → nx ≠ [] ∧ pstate.lnum = nx.last ∧ pstate.lnum ∈ gstore2, pstate.index? → pstate.lnum ∈ istore2 ⊦ dups(nx), ∃ err0. ⌊err0⌋ ∨ err0 = ESUCCESS

Proof step 10 from proof inv-recovery (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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