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Proof step 7 from proof inv-recovery (previous step)

adr0 = adr1, err = err0, ginval = ginval4, ginval0 = ginval2, ginval1 = ginval3, gstore = gstore1, gstore0 = gstore3, gstore3 = crash(gstore2, gstore1, ginval4, nx), istore = istore1, istore0 = istore3, istore3 = remove-refsize0(crash(istore2, istore1)), maxino0 = maxino1, nx0 = nx1, remove-refsize0(gstore1) = gstore1, remove-refsize0(istore1) = istore1, elems nx ∩ ginval4 = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ ginval4, inv(gstore2 \ ginval4), inv(gstore1), inv(istore2), inv(istore1), istore1 ⊑ istore2, pstate.journal? → nx ≠ [] ∧ pstate.lnum = nx.last ∧ pstate.lnum ∈ gstore2, pstate.index? → pstate.lnum ∈ istore2, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪if err = ESUCCESS then pstate := unbuffered, syn := true, adr0 := adr, maxino0 := maxino, nx0 := nx, ginval1 := ginval0 else pstate := ?, syn := ?, adr := ?, istore0 := ?, istore := ?, ginval := ?, gstore0 := ?, gstore := ?, nx := ?, maxino := ?, ginval0 := ?, adr0 := ?, maxino0 := ?, nx0 := ?, ginval1 := ?⟫ ( err = ESUCCESS → syn ∧ inv(gstore0 \ ginval) ∧ inv(gstore) ∧ elems nx ∩ ginval = ∅ ∧ ¬ dups(nx) ∧ dom gstore ∪ elems nx = dom gstore0 ∪ ginval ∧ remove-refsize0(gstore) = gstore ∧ inv(istore0) ∧ inv(istore) ∧ istore ⊑ istore0 ∧ remove-refsize0(istore) = istore ∧ (pstate.journal? → nx ≠ [] ∧ pstate.lnum = nx.last ∧ pstate.lnum ∈ gstore0) ∧ (pstate.index? → pstate.lnum ∈ istore0)), dups(nx)

Heuristic conditional right split applied rule if right

And obtained the following new goals

Rule argument

pos: right 1

Additional information