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Proof step 6 from proof inv-set-iblock-refsize (previous step)

ginval = ginval1, ginval0 = ginval2, gstore = gstore1, gstore0 = gstore2, maxino = maxino1, maxino0 = maxino2, remove-refsize0(istore0) = istore0, remove-refsize0(gstore1) = gstore1, elems nx ∩ ginval2 = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ ginval2, inv(istore0), inv(istore), inv(gstore1), inv(gstore2 \ ginval2), maxino0 ∈ istore, maxino2 ∈ istore, istore0 ⊑ istore, pstate = unbuffered → syn, pstate.index? → pstate.lnum ∈ istore, pstate.journal? → nx ≠ [] ∧ pstate.lnum = nx.last ∧ pstate.lnum ∈ gstore2 ⊦ dups(nx), inv(istore[maxino0, istore[maxino0].ref-size:= n]) ∧ istore0 ⊑ istore[maxino0, istore[maxino0].ref-size:= n] ∧ (pstate.journal? → nx ≠ [] ∧ pstate.lnum = nx.last ∧ pstate.lnum ∈ gstore2) ∧ (pstate.index? → pstate.lnum ∈ istore[maxino0, istore[maxino0].ref-size:= n]) ∧ (pstate = unbuffered → syn)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
remove-refsize0(istore0) = istore0, remove-refsize0(gstore1) = gstore1, elems nx ∩ ginval2 = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ ginval2, inv(istore0), inv(istore), inv(gstore1), inv(gstore2 \ ginval2), inv(istore[maxino2, istore[maxino2].ref-size:= n]), maxino2 ∈ istore, istore0 ⊑ istore, pstate = unbuffered → syn, pstate.index? → pstate.lnum ∈ istore, pstate.journal? → nx ≠ [] ∧ pstate.lnum = nx.last ∧ pstate.lnum ∈ gstore2 ⊦ dups(nx), (pstate.index? → pstate.lnum ∈ istore[maxino2, istore[maxino2].ref-size:= n]) ∧ istore0 ⊑ istore[maxino2, istore[maxino2].ref-size:= n]

Rule argument

Additional information

Used simplifier rules: ⊦ n ∈ istore ∧ inv(istore) → (inv(istore[n]) ↔ true); (ss)% ⊦ inv(iblock.ref-size:= n0) ↔ inv(iblock); (ss)% ⊦ inv(istore) → (inv(istore[n, iblock]) ↔ inv(iblock)); (ss)