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Proof step 2 from proof dom-disj-in-l (previous step)

dom gstore ∩ dom istore = ∅, n ∈ gstore ⊦ n ∈ istore ↔ false

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: dom-disj-in-r: ⊦ dom gstore ∩ dom istore = ∅ ∧ n ∈ istore → (n ∈ gstore ↔ false);%int-c: ⊦ ns ∩ ns0 = ns0 ∩ ns; from specification set-union[nat-set]%int-a: ⊦ (ns ∩ ns0) ∩ ns1 = ns ∩ ns0 ∩ ns1; from specification set-union[nat-set]