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Proof step 1 from proof elems-in-diff (conclusion)
⊦ n ∈ nx0 ∧ ¬ n ∈ nx1 → n ∈ elems nx0 \ elems nx1
System applied rule normalize
And obtained the following new goals
Proof step 2
:
n ∈ nx0 ⊦ n ∈ elems nx0 \ elems nx1, n ∈ nx1
Rule argument
Additional information