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Proof step 1 from proof elems-subseteq-add-diff-notin (conclusion)

⊦ ¬ n ∈ nx0 ∧ elems nx1 ⊆ elems nx0 → (elems nx0 ++ n) \ elems nx1 = (elems nx0 \ elems nx1) ++ n

System applied rule normalize

And obtained the following new goals

Proof step 2:
elems nx1 ⊆ elems nx0 ⊦ (elems nx0 ++ n) \ elems nx1 = (elems nx0 \ elems nx1) ++ n, n ∈ nx0

Rule argument

Additional information