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Proof step 11 from proof icrash-refsize-cons (previous step)

crash(istore1, istore0)[n].ref-size = (as | n).size, istore0[n] = indexblock(indx, lax, m), n ∈ istore0 ⊦ m = (as | n).size

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 12:
istore0[n] = indexblock(indx, lax, m), crash(istore1, istore0)[n] = indexblock(indx0, lax0, m0), m0 = (as | n).size, n ∈ istore0 ⊦ m = (as | n).size

Rule argument

spec: ablock, inst: index-store name: elim seq: ⊦ (indx = iblock.indlist ∧ lax = iblock.ladrlist) ∧ m = iblock.ref-size ↔ iblock = indexblock(indx, lax, m) subst: [iblock, indx, lax, m] → [crash(istore1, istore0)[n], indx0, lax0, m0]

Additional information

Used simplifier rules: ⊦ (indx = iblock.indlist ∧ lax = iblock.ladrlist) ∧ m = iblock.ref-size ↔ iblock = indexblock(indx, lax, m); (elim) Used terms: crash(istore1, istore0)[n], indx0, lax0, m0