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Proof step 6 from proof icrash-refsize-cons (previous step)

⊦ (∀ n. n ∈ istore0 → crash(istore1, istore0)[n].ref-size = (as | n).size) ↔ (∀ n. n ∈ istore0 → istore0[n].ref-size = (as | n).size)

User applied rule case distinction

And obtained the following new goals

Proof step 7:
∀ n. n ∈ istore0 → crash(istore1, istore0)[n].ref-size = (as | n).size ⊦ ∀ n. n ∈ istore0 → istore0[n].ref-size = (as | n).size
Proof step 15:
∀ n. n ∈ istore0 → istore0[n].ref-size = (as | n).size ⊦ ∀ n. n ∈ istore0 → crash(istore1, istore0)[n].ref-size = (as | n).size

Rule argument

pos: right 1

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